Selinsgrove, Pennsylvania Statistic: Population, Charts, Map, Steets and More

The population of Selinsgrove, Pennsylvania, is about 5,902 in the 2020 census. This city is located in the middle of the Susquehanna River valley along U.S. Routes 11 and 15. It is approximately 36.4 miles from Harrisburg and 5.7 miles from Sunbury. Selinsgrove is home to Susquehanna University. Founded by Captain Anthony Selin in 1790, Selinsgrove is a college town.

The median property value in Selinsgrove is $154,600. This is 0.64 times the national average. There are also 42 rent subsidized apartments, making them affordable to low-income families. Section 8 Housing Choice vouchers provide low-income residents with $300 per month in rent. The average voucher holder contributes approximately $400 towards their rent, which makes it possible for Selinsgrove residents to rent a two-bedroom apartment for between $716 and $876.

Renters in Selinsgrove City may qualify for rental assistance programs if they earn 80% of the area median income. These programs are targeted at low-income households and help those who cannot afford to pay full market rent. For more information about housing in Selinsgrove, PA, please visit the official city website. You can also use the links below to apply for federally-assisted housing.

Residents of Selinsgrove, PA are predominantly US citizens, 98.3% as of 2019 compared to 97.9% in 2018. Selinsgrove is also more likely to be a US citizen than the average neighboring town. The city also boasts a high percentage of military personnel who served during the Gulf War (1990s).